Abstract
We study the existence and multiplicity of homoclinic orbits for second-order Hamiltonian systems , where is unnecessarily positive definite for all , and is of at most linear growth and satisfies some twist condition between the origin and the infinity.
1. Introduction
Consider the following second-order non-autonomous Hamiltonian system where is a symmetric matrix-valued function, and denotes the gradient of with respect to . As usual, we say that a nonzero solution of (1.1) is homoclinic (to 0) if and as .
As a special case of dynamical systems, Hamiltonian systems are very important in the study of gas dynamics, fluid mechanics, relativistic mechanics and nuclear physics. While it is well known that homoclinic solutions play an important role in analyzing the chaos of Hamiltonian systems, if a system has the transversely intersected homoclinic solutions, then it must be chaotic. If it has the smoothly connected homoclinic solutions, then it cannot stand the perturbation, its perturbed system probably produces chaotic phenomena. For the chaos theory, the readers can refer to [1–3] and the references therein for more details. Therefore, it is of practical importance and mathematical significance to consider the existence of homoclinic solutions of Hamiltonian systems emanating from 0.
In the past years, the existence and multiplicity of homoclinic orbits for (1.1) have been extensively investigated in many papers via the variational methods. Most of them (see [4–13]) treated the case where and are either independent of or periodic in . In this kind of problem, the function plays an important role. If is neither a constant nor periodic, the problem is quite different from the ones just described, because of the lack of compactness of the Sobolev embedding. After the work of Rabinowitz and Tanaka [13], many results (see, e.g., [9, 14–22]) were obtained for the case where is neither a constant nor periodic. Among them, except for [13, 16, 18, 20–22], all known results were obtained under the following assumption that is positive definite for all , that is,
In the present paper, we will study the existence and multiplicity of homoclinic orbits for (1.1) under the condition that is coercive but unnecessarily positive definite for all . More precisely, satisfies the following conditions:()There exists an such that where is the smallest eigenvalue of , that is,
Before presenting the conditions on the nonlinearity of (1.1), we note that in the recent paper [23], under a twisting of the nonlinearity between the origin and the infinity, the authors studied the existence and multiplicity of nontrivial solutions for nonlinear elliptic equations and also for nonlinear elliptic systems. Subsequently, this kind of twist conditions and the idea of the methods in [23] were also applied to first-order Hamiltonian systems in [24].
Inspired by these works, we will present some similar twist condition on the nonlinearity of (1.1) to those in [23, 24], which will be specified in what follows.
Here, we introduce some notations. Denote by the set of all uniformly bounded symmetric matric functions. That is to say, if and only if for all and is uniformly bounded in as the operator on . For any , in the next section, we will define an index pair , satisfying .
With this index, we can present the conditions on and the nonlinearity as follows. For notational simplicity, we set , and in what follows the letter will be repeatedly used to denote various positive constants whose exact value is irrelevant. Besides, for two symmetric matrices and , means that is semipositive definite., and there exists a constant such that and ,there exists some and continuous symmetric matrix functions with and such that Our first result reads as follows.
Theorem 1.1. Assume , , , and hold. If then (1.1) has at least one nontrivial homoclinic orbit. Moreover, if and , the problem possesses at least two nontrivial homoclinic orbits.
Condition is a two-side pinching condition near the infinity, learning from the idea of [23, 24], we can relax to condition as follows.There exist some and a continuous symmetric matrix function with such that
The uniform boundary of displayed in condition can also be relaxed as, and there exists a constant such that For any , is bounded on .
On the other hand, we need some sharply twisted conditions than the above theorem, and we have the following theorems.
Theorem 1.2. Assume , , , , , and hold. If (or ), then (1.1) has at least one nontrivial homoclinic orbit.
Theorem 1.3. Suppose that , , , , , and are satisfied. If, in addition, is even in and (or ), then (1.1) has at least pairs of nontrivial homoclinic orbits.
Remark 1.4. Note that the assumption in is not essential for our main results. For the case of with , let with small enough, where is the identity map on , then and , and hence holds for . Therefore, Theorems 1.2 and 1.3 still hold in this case. While for the case of with , if we replace by in Theorems 1.2 and 1.3, then similar results hold. Indeed, let with small enough such that and , then this case is also reduced to the case of for with .
Remark 1.5. Choose instead of in (1.1), then conditions , , , and still hold for , so we can always assume .
2. Preliminaries
Denote by the self-adjoint extension of the operator with domain . Let and be the spectral resolution and the absolute value of , respectively, and let be the square root of with domain . Set , where is the identity map on . Then, commutes with , , and , and is the polar decomposition of . Let , and define on the inner product and norm by where denotes the usual inner product on . Then, is a Hilbert space. It is easy to see that is continuously embedded in . In fact, we further have the following lemmas.
Lemma 2.1 (see [16], Lemma 2.2). Suppose that satisfies . Then, is compactly embedded in with the usual norm for any .
From [16], under the assumption on and by Lemma 2.1, we know that possesses a compact resolvent. Therefore, the spectrum consists of only eigenvalues numbered in (counted with multiplicity), and the corresponding system of eigenfunctions forms an orthogonal basis in .
Let where the closure is taken with respect to the norm . Then, one has the orthogonal decomposition with respect to the inner product . Now, we introduce on the following inner product and norm: where with and correspondingly. Clearly, norms and are equivalent (cf. [16]). From now on, we take with inner product and norm as our working space.
Remark 2.2. Note that the decomposition with respect to the inner product is also orthogonal with respect to both inner products and . In what follows, we always denote by the orthogonal decomposition with respect to the inner products unless specified otherwise.
In view of Lemma 2.1 and the equivalence of the norms and , there exists a constant such that
Define the quadratic form on by Then by definition, we have for all , where are the respective orthogonal projections. Define the self-adjoint operators and by it is easy to check that is a compact operator and for all in .
For any , it is easy to see determines a bounded self-adjoint operator on , by , for any , we still denote this operator by , then is a self-adjoint compact operator on and satisfies We decompose the space as , so that is negatively definite on , null on , and positively definite on . From the definition of and the compactness of , we know that and are both finite dimensional. Denote
Define the functionals and on by Combining this with Lemma 2.1, we know that and are both well defined. Furthermore, we have the following:
Proposition 2.3. Let and be satisfied. Then, , and hence . Moreover, from the similarly argument in [13], one has all critical points of on are homoclinic orbits of (1.1).
Lemma 2.4. Let , , and be satisfied. Then, one has(1) satisfies (PS) condition,(2) for large enough, where .
Proof. Assume with as . That is, First, we prove is bounded in . For each , define by It is easy to verify that satisfies where is the constant in condition and is the identity map on . Since , , and , we can choose small enough, such that for each , satisfying and . Thus is reversible on and there is a constant , such that On the other hand, for , there is a constant depending on , such that for each , Choose in (2.15), we have As we claimed in the part of introduction, in (2.15) and (2.16), the letter denotes different positive constants whose exact value is irrelevant. Thus, from (2.11), (2.14), (2.16), and Lemma 2.1, we have in bounded in . Thus, there exists a subsequence such that is convergent in . By the definition of , we have which yields the convergence of and in . Additionally, passing to a subsequence, if necessary, is convergent in since . Thus, is convergent and the (PS) condition is verified. By Lemma 5.1 in Chapter II of [25], we have for large enough.
In order to prove Theorems 1.2 and 1.3, we need the following lemma which is similar to Lemma 3.4 in [23] and Lemma 3.3 in [24].
Lemma 2.5. Assume , , and hold, then there exists a sequence of functions: satisfying the following properties:(1)there exists an increasing sequence of real numbers such that (2)for each , there is a such that for small enough;(3)there exist some such that (4)for each , there exists some and a constant with , such that where is the identity map on .
Proof. Define by
It is easy to see that . Choose a sequence of positive numbers such that as . For each , let and
As in [23, 24], we can easily check that satisfies (2.20), (2.22) (with ), (2.23) and (2.24) for each .
Define
where is a cut-off function with for and for . If we choose large enough, then will satisfy (2.20)–(2.24).
Remark 2.6. Similar to Remark 1.4, we can choose small enough in (2.22) such that and , that is, and .
Remark 2.7. For the case of , the sequence constructed in (2.26) will also satisfy (2.20), (2.21), (2.23), (2.24) (with and ) and with small enough, therefore, and .
Define Form Lemma 2.1 and (2.21) in Lemma 2.5, we have . Similarly, we can define and for all in , and it follows that .
Lemma 2.8. For each , satisfies the (PS) condition and the critical-point set is a compact set.
Proof. For any , assume with as : By (2.23) and (2.27), there hold for some . Choose with , then there exists a constant such that Since , and has bounded inverse, from Lemma 2.1 and (2.30), (2.32), we have is bounded in . From the similar argument in Lemma 2.4, has a convergent subsequence and the (PS) condition is verified. From the same reason, we can also prove that is compact set.
From Lemma II.5.1 in [25], by standard argument, we have the following.
Lemma 2.9. For any , there is an with large enough such that where .
Note that is an isolated critical point of since . For each , let , then is also compact since is compact. Then we have
Lemma 2.10. For any small enough, for each , there exists a functional such that(1),(2), ,(3),where . Moreover, satisfies the (PS) condition and has only a finite number of critical points, all nontrivial critical points of lie in and are nondegenerate.
Proof. We follow the idea of [26], since is a compact subset of , for every , there exists a function , with all its derivatives bounded and
Let , . We use the Sard-Smale Theorem to find , with , and is a regular value for . For any , the functional is defined by
By the fact and the definition of , it is easy to check that conclusions (1), (2), and (3) hold. Since and is a regular value for , then all nontrivial critical points of are nondegenerate and lie in .
In order to prove that satisfies the PS condition for each , assume there is a sequence such that , . From the definition of , we have for all . So , when is large enough. From the definition of and the proof in Lemma 2.8, we know that satisfies the (PS) condition and hence has a finite number of critical points.
3. Proof of the Main Results
From Lemma 2.4, Theorem 1.1 is a direct consequence of Theorem 5.1 and Corollary 5.2 in chapter II of [25].
Proof of Theorem 1.2. We first consider the case of . We divide the proof into two steps and follow the ideas of [24].Step 1. We claim that has a nontrivial critical point with its Morse index satisfying
Note that is a critical point of . The Morse index of 0 for is , since ,
If has only finite critical points, consider Morse inequality:
where , and is large enough such that .
By Lemmas 2.8 and 2.9, we have
where . Since , the right side of the inequality is equal to 0. If has no nontrivial critical point with its Morse index less than , the left side of the inequality is equal to −1, it is a contradiction.
If has infinitely many critical points. Assume for any ,
then from Lemma 2.10, we can choose small enough such that(1), so 0 is also an isolated critical point of and has the same Morse index ;(2)for any , is the dimension of the negative subspace of , satisfying . (Because is continuous, we can assume this.)
From (3) in Lemma 2.10, if is a nontrivial critical point of , the Morse index satisfies
Then choose satisfying , that is, . So,
Then, will not satisfy the Morse inequality. It is a contradiction.Step 2. We show that is bounded in , so from the definition of , is a nontrivial critical point of for large enough.
We prove it indirectly, assume , from (2.4), we have . Denote . Passing to a subsequence, we assume that for some ,
Since satisfies , we have
which implies for each and thus .
For each , let . By , (2.20), and (2.23), there holds for all . Assume in , then , almost everywhere in . By standard argument, we have
By Lemma 3.1 in [23], we have almost everywhere in , which implies almost everywhere in . For any ,
By , (2.20), and (2.22), is uniformly bounded from below. Using Fatou’s Lemma, we have
which implies
which contradicts to . So is bounded in , and has a nontrivial critical point.
In order to prove the case of , we choose with and in Lemma 2.5, then, using the similar argument as in Step 1 for the case of , we can also prove that there exists a nontrivial critical point of satisfying
As in Step 2 for the case of , we will show that is bounded in . We prove it indirectly, assume , almost everywhere in . We claim there exists such that if , then for any ,
which implies . If (3.15) is false, then there exist and with such that , which can be rewritten as
Passing to a subsequence if necessary, we assume that in and almost everywhere in for some with . Since
we see that
From (3.17) and (3.19), we have
If , it is a contradiction, or we have
which is also a contradiction. Thus, is bounded in and has a nontrivial critical point. By Proposition 2.3, (1.1) has a nontrivial homoclinic orbit. The proof is completed.
The proof of Theorem 1.3 is similar to the proof of Theorem 1.2. The difference is in Step 1, instead of Morse theory we make use of minimax arguments for multiplicity of critical points.
Let be a Hilbert space and assume is an even functional, satisfying the (PS) condition and . Denote .
Lemma 3.1 (see [27], Corollary 10.19). Assume and are subspaces of satisfying . If there exist and such that then has pairs of nontrivial critical points , so that , for .
First, we consider the case of , since is even, we have is also even, and it satisfies Lemma 2.5. Let , and , and we have , , . Then, it is easy to prove that satisfies Lemma 3.1 for and large enough. So, has pairs of nontrivial critical points: and pairs of them satisfying Then, we can complete the proof. In order to prove the case of , we need the following.
Lemma 3.2 (see [25], Corollary 4.1). Assume and are subspaces of satisfying . If there exist , and such that then has pairs of nontrivial critical points so that for .
The proof is similar to the case of , we omit it here.
Acknowledgment
This work is partially supported by NFSC (11126154) and by NFSC (11126146).