Abstract
We investigate the growth of solutions of higher-order nonhomogeneous linear differential equations with meromorphic coefficients. We also discuss the relationship between small functions and solutions of such equations.
1. Introduction and Main Results
Let be a meromorphic function in the whole complex plane. Throughout this paper, we assume that the reader is familiar with the fundamental results of the Nevanlinna’s value distribution theory of meromorphic functions and the standard notations such as the order , the exponent of convergence of zero-sequence , and the exponent of convergence of the sequence of distinct zeros . Moreover, a meromorphic function is called a small function with respect to if as , possible outside of a set of with finite measure, where is the Nevanlinna characteristic function of . The study of oscillation of solutions of linear differential equations has attracted many interests since the work of Bank and Laine; for more details see [1]. One of the main subject of this research is the growth and zero distribution of solutions of linear differential equations. In this paper, we first discuss the growth of solutions of higher-order linear differential equation where , and are entire functions of finite order. Some results on the growth of solutions of (1.1) have been obtained by several researchers, see [2–4]. In the case that the coefficients are polynomials, the growth of solutions of (1.1) has been extensively studied; see [2]. In 1992, Hellerstein et al. [3] proved that every transcendental solution of (1.1) is of infinite order, if there exists some such that . As for sectorial growth conditions on the coefficients of (1.1) that imply that all solutions are of infinite order, see, for example, [5]. In addition, a special case for this was investigated by Wang and Laine [6]. Recently, Wang and Laine [4] obtain the following.
Theorem A. Suppose that where are polynomials with degree , are entire functions of order less than , not all vanishing, and is an entire function of order less than . If are distinct complex numbers, then every solution of (1.1) is of infinite order.
Thus a natural question is whether every meromorphic solution of (1.1) has infinite order, if the coefficients of (1.1) are meromorphic? The following theorem partially answers this question.
Theorem 1.1. Let , and be meromorphic functions with , and let be complex constants such that (i) and or (ii) . Then every meromorphic solution of the equation satisfies .
Remark 1.2. In Theorem 1.1, if are replaced by , with additional hypothesis on similar to , and furthermore is replaced by , then we have the same conclusion with Theorem 1.1.
In 2000, Chen [7] first studied the fixed points of solutions of second-order linear differential equations and obtained some precise estimation on the number of fixed points. After that, a number of results on fixed points of solutions of differential equations with entire coefficients were obtained; see [8–10]. In 2006, Chen and Shon [11] further studied the relation between small functions and solutions of differential equations and obtain the following.
Theorem B. Let be entire functions with , and let be complex constants such that and or . If is an entire function with finite order, then every solution of equation satisfies .
Motivated by Theorem B, we try to consider the relation between small functions with meromorphic solutions of (1.2). Indeed, such relationship on higher order differential equations is more difficult than that of second order differential equations. Moreover, the method used in the proof of Theorem B cannot deal with the case of higher-order linear differential equations.
Theorem 1.3. Under the assumption of Theorem 1.1, if is a meromorphic function of finite order and satisfies , then every non-trivial meromorphic solution of (1.2) satisfies .
Remark 1.4. As the remark on Theorem 1.1 in Remark 1.2, the conclusion of Theorem 1.3 can also be extended to the case that are replaced by , with some similar additional hypothesis on , and in Theorem 1.3.
2. Preliminary Lemmas
To prove our theorems, we need some lemmas.
Lemma 2.1 (see [12]). Let be a transcendental meromorphic function with . Let be a finite set of distinct pairs of integers satisfying for . Also let be a given constant. Then, there exists a set that has finite logarithmic measure, such that for all satisfying and for all , One has
Let is a nonconstant polynomial and are real constants. For , set .
Lemma 2.2 (see [13]). Let be a non-constant polynomial of degree . Let be a meromorphic function, not identically zero, of order less than , and set . Then for any given there exists a zero measure set such that if , then for .(1)If , then ;(2)If , then , where is a finite set.
Lemma 2.3 (see [14]). Let be finite-order meromorphic functions. If is an infinite-order meromorphic solution of the equation then satisfies .
Lemma 2.4 (see [15], page 79). Suppose that are meromorphic functions and are entire functions satisfying the following conditions:(1);(2) are not constants for ;(3)For , , where has a finite measure.
Then .
Lemma 2.5 (see [4], Lemma 2.6). Let be a an entire function of order . Suppose that there exists a set which has linear measure zero, such that for any ray , where is a positive constant depending on , while is a positive constant independent of . Then .
Lemma 2.6 (see [16]). Let be a transcendental meromorphic function of order . Then for any given , there exists a set which has linear measure zero, such that if , then there is a constant such that for all satisfying and , One has
3. Proof of Theorem 1.1
Assume that is a meromorphic solution of (1.2) of finite order. We will deduce a contradiction later. First, we have . Otherwise, it follows from Lemma 2.4 that which is a contradiction.
Since is a meromorphic solution of (1.2), we know that the poles of can occur only at the poles of and . Let , where is the canonical product formed with the nonzero poles of , with , and is an entire function with . Substituting into (1.2), by some calculation we can get where are defined as a sum of a finite number of terms of the type are constants, and . Now, we rewrite (3.1) into
Set . By Lemma 2.1, for any given there exists a set which has linear measure zero, such that if , then there is a constant such that for all satisfying and , we have Meanwhile, by Lemma 2.6, for the above there exists a set of zero linear measure, such that if , we have for sufficiently large , Next we divide our proof into two cases.
Case 1. Suppose that and . Then for any ray , we have
By Lemma 2.2, for any given we can find a ray , where and are defined in Lemma 2.2, has zero linear measure, such that , and for sufficiently large ,
Thus, by (3.4) and (3.7), we have for sufficiently large ,
where are positive constants.
For , we claim that
is bounded on the ray . Otherwise, there exists a sequence of points , such that , and that
From (3.10) and the definition of order, we see that
for is large enough.
By (3.3),(3.4), and (3.8)–(3.11), we get for sufficiently large ,
Clearly, we can choose sufficiently small such that . Then by (3.12), we can obtain a contradiction provided that is sufficiently large.
Therefore,
is bounded, and we have on the ray .
Case 2. Suppose that . By Lemma 2.2, there exists a ray , where , and are defined, respectively, as in Case 1, such that
Further, for any given , we have for sufficiently large ,
Thus, by (3.4) and (3.15), we have for sufficiently large ,
where are positive constants.
For , we claim that
is bounded on the ray . Otherwise, there exists a sequence of points , such that , and that
From (3.18) and the definition of order, we see that
for is large enough.
Then by similar reasoning as in Case 1, we can also obtain a contradiction. So
is bounded, and we have on the ray .
Combining Case 1 and Case 2, for any given ray , of linear measure zero, we have on the ray , provided that is sufficiently large. Thus by Lemma 2.5, we get , which is a contradiction. Again by Lemma 2.3, we complete the proof of Theorem 1.1.
4. Proof of Theorem 1.3
Let be a meromorphic solution of (1.2). Set . First, we prove that .
Set . By Theorem 1.1, we have . Substituting into (1.2), we get We remark that (4.1) may have finite-order solutions, but we only need to discuss the solutions whose order are .
If , then by Theorem 1.1, we have . It is a contradiction. Hence we have . It follows from Lemmas 3 and (4.1) that .
Now we prove that . Set . Differentiating both side of (1.2), we get Rewriting (1.2), we have Substituting (4.3) into (4.2), we get We rewrite (4.4) into the following form: where . Substituting into (4.5), we have
Next we prove Conversely, assume that .
Dividing into both sides of , we have where Set . Clearly from (4.9), Meanwhile, by (4.9), we have outside a possible exceptional set of finite linear measure. On the other hand, again by (4.9), we have Combining (4.11) and (4.12), we get By Lemma 2.6, for any given positive constants , there exists a ray , where has zero linear measure, such that for sufficiently large , Therefore by (4.13), and Lemma 2.2, we can find a ray , where and are defined in Lemma 2.2, has zero linear measure, such that , and for sufficiently large , Thus, by (4.8) and (4.14) and (4.15), we have Since can be chosen arbitrarily small, we can obtain a contradiction. Thus we have . By Lemma 2.3 and (4.6), we get .
Acknowledgments
The author would like to thank the referee for his/her valuable suggestions and comments. This research is supported by NNSF of China (no. 11001057), NSF of Jiangsu Province (BK2010234), Project of Qinglan of Jiangsu Province.