Abstract

This paper is concerned with the inverse eigenvalue problem for singular rank one perturbations of a Sturm-Liouville operator. We determine uniquely the potential function from the spectra of the Sturm-Liouville operator and its rank one perturbations.

1. Introduction

Consider the boundary problem on with where is real valued, , , and are the Dirac delta function. It is well known [1] that the operator is a self-adjoint operator in , which is a singular rank one perturbation of the Sturm-Liouville operator .

The goal of this paper is to deal with the inverse problem of recovering the potential in (1) from the spectra of and , by applying the method in [1] and the perturbation theory for linear operators [2]. Note that in [3], the boundary problem with (2) and the discontinuous conditions can be regarded as the problem (1)-(2). The research of this paper can be a variation of Borg’s two-spectra theorem [4] for the second spectrum that is obtained by attaching the interface conditions (4) and (5) to the problem (3) and (2). Our immediate motivation is a recent research of del Rio and Kudryavtsev [5, 6], who considered the inverse problem for Jacobi matrices and recovered the original matrix from the spectra of it and its interior mass-spring perturbation; they indicated that the uniqueness for the inverse problem does not remain valid in general; however, under certain conditions, there exists at most a finite number of matrices corresponding to the two spectra.

Such operator appears not only in electronics but in other areas such as the theory of diffusion processes, see the related references in [7, 8]. Some spectral and inverse spectral problems for the Sturm-Liouville operator with rank one perturbations have been investigated in [1, 3, 920]. In particular, Albeverio, Hryniv, and Nizhnik [3] considered the inverse eigenvalue problem for the Sturm-Liouville operator with the point potential and the perturbation where and . Later, Nizhnik [16] continued the problem with . However, we consider the inverse problem for the operator (1) with the potential and the perturbation . And the potential may not be determined uniquely just by the spectra; so, we employ the addition information. Moreover, the approach we use can also solve the problem with the perturbation in the research [18]. In the paper, we establish the expression of the characteristic function of which provides a necessary preliminary for treating with its inverse eigenvalue problem. The approach we use to prove our results can convert the problem (1) and (2) into three spectra inverse problem in [21, 22]. Actually, the spectra of and may not determine the potential uniquely (see Remark below for details). The key difficulty encountered is to identify the eigenvalues of two Sturm-Liouville problems defined on and from the knowledge of the spectra of and , for which we have to employ addition information of the number of zeros of the eigenfunctions, and the condition two spectra are disjoint.

The main result asserts that, if the spectra of and are disjoint, the potential can be determined uniquely by the spectra of and and the numbers of zeros, contained in , of all eigenfunctions of . We will state and prove it in the next section.

2. The Main Theorem and Proof

We describe some preliminaries which will be needed subsequently, due to [1]. One defines the scale of spaces associated to as follows. The space is with the norm in which is easily seen to be complete. For , take with the norm given by and complete it. Note that and are dual in such a way that is associated to the function given by . A Sobolev estimate shows that, for any , that is, lies in . Hence, by Section 2 in ([1], p. 115) Simon, one can find a spectral measure such that

By (I.15) and (I.16) in ([1], p. 116), it follows that

The following preliminaries are due to ([2], p. 245-250). The multiplicity index for is given by

The multiplicity function for a closed operator is defined by

Let be the eigenvalue of , . Then,

Using the same way as the proof of the W-A formulas in ([2], p. 248), by (10), we deduce

In the following lemma, we give the spectrum and a characteristic function of .

Lemma 1. The spectrum of consists of real eigenvalues. The characteristic function of is where is the characteristic function of .

Proof. By (9), where is Green’s function for . From ([23], p. 15, p.29), is meromorphic with simple poles in the points . Then, for , it follows Notice that the spectrum of consists of simple real eigenvalues. Combining with Theorem I.6 in [1], we see Thus, by Theorem II.2 in [1] and (18), the spectrum of consists of real eigenvalues, denoted by .
By (14), each zero of is an eigenvalue of . Hence, the zeros of are real and consist of the zeros of . Let be the zeros set of . Then, we have the multiplicity function Using (14), it follows Hence, by the definition of , we have Now, we prove that, for , , if and only if . In fact, if , it is easily seen that . We just prove that if , then . Suppose that and , then , i.e., is a pole of . By Theorem 1.1.2 in [23], all zeros of are simple; so, By (15), (16), and ([23], p. 15), is derivable; thus, which is contradictory to that which is the pole of . Then, .
For we also need to prove that is an eigenvalue of of multiplicity if and only if is a zero of of multiplicity . Actually, if is an eigenvalue of of multiplicity , then by (21), there is , and it is easily to get Now, we suppose that is a zero of of multiplicity , i.e., (26) holds. By , there is or . Combining with there is and which mean . Then, is an eigenvalue of of multiplicity . The proof is complete.☐

The main result in this paper is as follows.

Theorem 2. Let and be the spectrum of and , respectively. If , the potential can be determined uniquely by and the numbers of zeros, contained in , of all eigenfunctions of .

Proof. By Theorem 1.1.4 in [23], the characteristic function of can be calculated by In the same way of the proof of Theorem 1.1.4 in [23], by Hadamard’s factorization theorem [24], the characteristic function of can be calculated by From the given spectra , we can determine the function by From (16), ([23], p. 15) and (2) in [23], where and are the solutions of (3) under the initial conditions and . Then, we get the zeros of , denoted by . It should be noted that where and are the spectra of the following problems respectively.
If , is the pole of , and is the zero of . Using (18), it implies that is monotonically increasing on . By (16) and ([23], p. 29, [30]), Consequently, there is no zero of in and exactly one zero in . That means We identify and from by virtue of the number of the zeros of the eigenfunction contained in . As is known ([25], p. 15) that the eigenfunction has exactly zeros in , we suppose that the eigenfunction has () zeros in . By comparison theorem in ([25], p14), there are not fewer than zeros of the eigenfunction contained in . From Lemma 1.3.1 in [25], the roots of depend continuously on . Combining with Corollary 1.3.2 in [25], has zeros in only if there exists such that . Therefore, if has zeros in , then ; otherwise, . Then, we obtain and from with the information of the number of zeros of the eigenfunctions contained in .
Next, we prove that , , and determine . By (35) and Theorem 3.2 in [21], we see that , , and can uniquely determine , a.e., on . The proof is therefore complete.☐

Remark 3. Based on the proof of Theorem 2, we know that two disjoint spectra and determine uniquely rather than and . Thus, in order to obtain the uniqueness of , we need to identify and from . To this end, we have to employ the number of zeros of eigenfunctions, and the condition two spectra are disjoint, if not, we may not guarantee the uniqueness of . For example, if , then the eigenvalues of and have the following asymptotic expressions: where and . It is easy to see that there exists a positive integer such that, for while we cannot identify and from for , which means that there will be at most a finite number of corresponding to two spectra and in virtue of Theorem 3.2 in [21]. Hence, we employ the number of zeros of eigenfunctions, and the condition two spectra are disjoint to guarantee the uniqueness of . And we have not found an example that the joint spectra determine the potential uniquely.

Data Availability

No data were used to support this study.

Conflicts of Interest

The author declares that there are no conflicts of interest regarding the publication of this paper.

Authors’ Contributions

The author conceived of the study, drafted the manuscript, and approved the final manuscript.

Acknowledgments

The author is very grateful to the handling editors and the reviewers for the careful reading of this manuscript and offering valuable comments for this manuscript.