Periodic Solutions to a Third-Order Conditional Difference Equation over the Integers

Figure 2

Equation (1.4) 𝑟=−7/15. (a): Initial values 𝑦₀=10, 𝑦₁=2, 𝑦₂=18(𝑡=2); (b): Initial values 𝑦₀=55, 𝑦₁=11, 𝑦₂=99(𝑡=11).

(a)

(b)