A Lot-Size Model for Deteriorating Items under Conditions of a One-Time Only Extended Credit Period

Table 2

Optimal solution for extended credit period.

𝑁	Δ2	𝑇𝑠	𝐾𝑖(𝑇𝑠)	𝑍𝑖(𝑇𝑠)
30/365	493.15	𝑇𝑠2 = 0.0963	𝐾2(𝑇𝑠2) = 49.97	−8.53
45/365	739.73	𝑇𝑠1 = 0.1065	𝐾2(𝑇𝑠2) = 46.17	−18.53
60/365	986.30	𝑇𝑠1 = 0.1167	𝐾2(𝑇𝑠2) = 40.84	−30.06
75/365	1232.88	𝑇𝑠1 = 0.1268	𝐾2(𝑇𝑠2) = 33.96	−43.07