Collocation Method via Jacobi Polynomials for Solving Nonlinear Ordinary Differential Equations

Figure 1

Numerical solution of our example for different values of 𝛼 and 𝛽. (𝑎₁)𝛼=0, 𝛽=0;(𝑎₂) is error. (𝑏₁)𝛼=−0.4, 𝛽=−0.4;(𝑏₂) is error. (𝑐₁)𝛼=−0.5, 𝛽=−0.5;(𝑐₂) is error. (𝑑₁)𝛼=−0.4, 𝛽=0.6;(𝑑₂) is error. (𝑒₁)𝛼=0.6, 𝛽=0.6;(𝑒₂) is error. (𝑓₁)𝛼=2, 𝛽=2;(𝑓₂) is error.

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