A New Noninterior Continuation Method for Solving a System of Equalities and Inequalities

Table 5

Numerical results for Examples 1′–4′.

Example	ST	Our algorithm		Algorithm in [8]
		IT	CPU	IT	CPU
Example 1′	(0,0,0)^𝑇	8	0.007767	6	0.006365
	(−1,−1,−1)^𝑇	6	0.006270	8	0.007373
	(1,1,1)^𝑇	8	0.006578	7	0.006137
Example 2′	(0,0,0)^𝑇	12	0.016807	49	0.068499
	(−1,−1,−1)^𝑇	12	0.017554	45	0.065420
	(1,1,1)^𝑇	10	0.026884	54	0.187465
Example 3′	(0,0,0)^𝑇	13	0.011897	5	0.004939
	(−1,−1,−1)^𝑇	5	0.007156	18	0.023658
	(1,1,1)^𝑇	5	0.006765	11	0.010136
Example 4′	(0,0,0)^𝑇	18	0.030636	—	—
	(0,0,1)^𝑇	17	0.036194	—	—
	(1,0,1)^𝑇	19	0.043265	—	—