Abstract
The solvability of the fractional partial differential equation with integral overdetermination condition for an inverse problem is investigated in this paper. We analyze the direct problem solution by using the “energy inequality” method. Using the fixed point technique, the existence and uniqueness of the solution of the inverse problem on the data are established.
1. Introduction
This work devoted to study the solvability of a pair of functions satisfying the following fractional parabolic problem: with the initial condition the boundary condition and the nonlocal condition
Here, is a bounded domain in with smooth boundary . The functions , , and are known functions, and is a positive constant. And denotes the gamma function. For any positive integer , the left Caputo derivative is defined as
Inverse parabolic equation problems occur naturally in many fields, and there is extensive literature on inverse heat equation problems (see [1–4], and references therein). The form (4) is an additional information of problem.
In engineering and physics, the parameter recognition in a partial differential equation from the data of the integral overdetermination condition plays an important role [5–10]. From a physical point of view, these conditions can be interpreted by a system averaging the domain of spatial variables as measurements of the temperature .
Note that nonlocal problems related with integral overdetermination [11, 12]. Studies have shown that when we deal with these kinds of nonclassical problems, classical approaches sometimes do not work [13, 14]. To date, different methods for addressing problems resulting from nonlocal problem have been suggested. The choice of approach depends on the form of nonlocal boundary value that are involved.
We note that several authors have studied the inverse parabolic problem with condition of type (4) and its special solubility (see, for example, [3, 4, 15–20]). There are also several articles dedicated to the study of the existence and uniqueness of inverse problem solutions for different parabolic equations with unknown source functions. Inverse problems related by determining unknown function in source term of a parabolic equation with overdetermination condition [21, 22].
In recent years, fractional differential equations have created growing interest from engineers and scientists and have great importance in modeling complex phenomena. Because FDEs have memory, nonlocal space, and time relationships, using these equations, complex phenomena can be modelled [23–28].
Namely, in the present paper, a new research on the inverse problem of a fractional parabolic equation is discussed, for which the solvability of the problem (1)–(4) is reduced to the concept of a fixed point technique. This work is divided into four sections; we start with an introduction then we give some definitions of function space and important lemmas. The third section is devoted to studying the solvability of the direct fractional parabolic problem. Finally, in the last section, we prove the existence and uniqueness of the solution to the main problem.
2. Functional Space
Definition 1. Let us introduce certain notations used below, we set We denote by the space is composed of all continuous functions on with values in . For any , the Caputo and Riemann-Liouville derivatives are defined, respectively, as follows: (i)The left Caputo derivatives: (ii)The left Riemann-Liouville derivatives: (iii)The right Riemann-Liouville derivatives:
Many authors believe that the Caputo version is more natural because it makes it easier to manage inhomogeneous initial conditions. Then, the following relationship is related to the two concepts (7) and (8), which can be checked by a direct calculation:
Definition 2 (see [29]). For any real , we define the space as the closure of with respect to the following norm : where
Definition 3. For any real , we define the space as the closure of with respect to the following norm : where
Lemma 4 (see [29, 30]). For any real , if and , then
Lemma 5 (see [29, 30]). For , , on a
Lemma 6 (see [29, 30]). For , the seminorms and are equivalent. Then, we pose
Lemma 7 (see [29]). For any real , the space with respect to the norm (11) is complete.
Definition 8. We denote by the space of square functions, integrated with the scalar product in the Bochner sense, Since the space is a Hilbert space, it can be shown that is a Hilbert space as well. Let denote the space of infinitely differentiable functions on and denote the space of infinitely differentiable functions with compact support in .
3. Solvability of the Direct Fractional Parabolic Problem
3.1. Position of Problem
In the rectangular domain , with and , we shall study the existence and uniqueness of solutions to the following fractional parabolic problem:
We consider the following fractional parabolic equation of the type with the initial condition and Dirichlet condition where and are known functions.
We shall assume that the function satisfies a compatibility conditions, i.e.,
Now, introducing a new function where
So, we get
Such that with the initial condition the boundary condition of Dirichlet type where
3.2. A Priori Estimate
In this section, we illustrate the existence and uniqueness of the problem’s solution (27)–(29) as a solution of the operator equation where , with domain of definition consisting of functions , such that , , and verify (29).
The operator is considered from to , where is the Banach space consisting of all functions having a finite norm and is the Hilbert space consisting of all elements for which the norm is finite.
Theorem 9. For any function we have the inequality where is a positive constant independent of .
Proof. Multiplying equation (27) by the following function: and integrating over , we get As , so by applying Lemmas 4, 5, and 6 becomes and by integration by parts over , we get So, we obtain So, we get which give So, we have On the other hand, we have Also, we have By combining (41), (42), and (43), for , we get Finally, it follows that with Therefore, we obtain that Hence, the uniqueness of the solution.
Remark 10. This inequality gives the uniqueness of the solution, indeed:
Let and two solutions, so
then
which gives the uniqueness of the solution.
Proposition 11. The operator from to admits a closure.
Proof. Let be a sequence such that: it must be shown that The convergence of toward in entails that As the continuity of the fractional derivation(2) and the derivation of the first order (as a particular case of the fractional derivative) of in , then (52) implies On the other hand, the convergence of to in implies that By virtue of the uniqueness of the limit in , we conclude between (53) and (54) that Hence, the operator is closable.
Definition 12. Let the closure of and the definition domain of . The solution of the equation is called generalized strong solution of the problem (27)–(29).
Theorem 9 is valid for a generalized strong solution, i.e., we have the following inequality:
Consequently, this last inequality entails the following corollaries:
Corollary 13. The strong solution of the problem (27)–(29) is unique and depends continuously on .
Corollary 14. The range of the operator is equal to the closure of .
Proof. Let , then there exists a Cauchy sequence in consists of the elements of the set such that
So there is a corresponding sequence such that
From the estimate (41), we obtain
We can deduce that is a Cauchy sequence in , so there is By virtue of the definition of ( in ; if , so and as is closed so ), the function verifies that
Thus, , then
So we conclude here that is closed because it is complete (any complete subspace of a metric space (not necessarily complete) is closed).
It remains to show the opposite inclusion.
Let , then there is a sequence of in consists of the elements of the set such that
where , because is closed subset of a complete space ; then, is complete.
So there is a corresponding sequence such that
From the estimate (57), we obtain
We can deduce that is a Cauchy sequence in , so there is Once more, there is a corresponding sequence such that
Then
Consequently, , and then, we conclude that
3.3. Existence of Solution
To show the existence of solutions, we prove that is dense in for all and for arbitrary .
Theorem 15. The problem (27)–(29) admits a solution.
Proof. The scalar product of is defined by
If we put , we have
where , , , with satisfies the boundary conditions of (27)–(29). From (72), we get the equality
And from the equality (73), we give the function in terms of as follows:
then .
Replacing in (73) by its representation (74) and integrating by parts each term of (73) and by taking the condition of , we obtain
then
Hence
And thus, in which gives in . This proves Theorem 15. So .
4. Existence and Uniqueness of the Solution of Main Problem
We are finding a solution in the form of the original inverse problem. where is the solution of the direct problem while the pair is the solution of the inverse problem where
We will assume that the functions that appear in the problem data are measurable and fulfill the following conditions:
The correspondence between and can be seen as one way of defining the linear operator. with the values
In this view, the linear equation of the second form for the function is rational to refer to over the space where
Remark 16. As where is the solution of the direct problem (78)–(80). Obviously, the previous section implies that exists and is unique, but instead of demonstrating the solvability of the initial problem (1)–(4), we demonstrate the existence and uniqueness of the inverse problem (81)–(84) solution.
Theorem 17. Suppose the input of the inverse problem data (81)–(84) satisfies . Then, the following assertions are valid: (i) if the inverse problem (81)–(84) is solvable, then so is equation (89). And (ii) if equation (89) has a solution and the condition of compatibility has holds, then a solution to the inverse problem exists.
Proof. (i)Suppose that the inverse problem (81)–(84) is solvable. We denote its solution by . Multiplying the function scalarly in both sides of (81), we getWith (84) and (88), from (92), it follows that . This gives that solves equation (89).
(ii)Equation (89) has a solution in space, according to the assumption, , say . The resulting relationship (81)–(83) can be viewed as a direct problem with a unique solution when inserting this function in (81). Let us show that the function also satisfies the condition of integral overdetermination (84). By equation (92), the function is subject to the following relationSubtracting equation (92) from equation (93), we get
Integrating the preceding differential equation and taking into account the compatibility condition (89), we find that the overdetermination condition (84) is satisfied by and the function pair is a solution to the inverse problem (81)–(84).
This completes the theorem’s proof.
Now, we are touching on some properties of operator .
Lemma 18. Let the condition hold. Then, there exists a positive for which is a contracting operator in .
Proof. Obviously, (88) yields the estimate where Multiplying both sides of (81) by scalarly in and integrating the resulting by parts with use of (82), we get Thus, by using the Cauchy’s -inequality, we obtain Choosing we get Omitting some terms on the left-hand side (99) leads to According to (95) and (100), we can obtain the following estimate: where So, we obtain It is obvious from the above that there is positive such that Inequality (103) shows that the operator is a contracting mapping on .
The following result may be useful with respect to the particular solvability of the inverse problem concerned.
Theorem 19. Let the compatibility condition (91) and the condition hold. Then, the inverse problem (81)–(84) has a unique solution .
Proof. This means that the equation (89) has a unique solution in .
The existence of a solution to the inverse problem (81)–(84) is verified, according to Lemma 6.
The uniqueness of this solution has yet to be proven.
Suppose the contrary that there are two distinct solutions and of the under consideration inverse problem.
Also, the linear operator is contracting on from Lemma 18, which gives that ; then, by the theorem of the uniqueness of the solution of main direct problem (78)–(80), we will just have .
Corollary 20. The solution to equation (91) depends continuously, under the conditions of Theorem 19, on the data .
Proof. Let and twosets of data that satisfy Theorem 19’s assumptions.
Let and be solutions of the equation (89) corresponding to the data and , respectively. According to (103), we have
Let us estimate the difference first, . It is easy to see with the use of (103) that
so, we get
5. Conclusion and Perspectives
This work contains a new inverse problem by investigating the fractional derivatives where we develop the method of fixed point and energy inequality method for proving the solvability of an inverse fractional problem. We note that our work extends to the existence of open problems as a study of the nonlinear case of this problem and the numerical part.
Data Availability
No data were used to support this study.
Disclosure
An earlier version of this manuscript has been presented as online conference in Modern Fractional Calculus and Its Applications (OCMFCA-2020) Biruni University Istanbul Turkey.
Conflicts of Interest
The authors declare no conflict of interest.
Acknowledgments
The research was supported by the Taif University Researchers Supporting Project number (TURSP-2020/77), Taif University, Taif, Saudi Arabia.