Generalized Complementarity Problem with Three Classes of Generalized Variational Inequalities Involving Operation

Table 2

The values of with initial values , , and .

No. of	For	For	For
Iteration
n = 1	−0.714285714285714	−1.42857142857143	−2.14285714285714
n = 2	0.102040816326531	0.204081632653061	0.306122448979592
n = 3	−0.0145772594752187	−0.0291545189504373	−0.0437317784256560
n = 4	0.00208246563931695	0.00416493127863390	0.00624739691795085
n = 5	−0.000297495091330993	−0.000594990182661986	−0.000892485273992979
n = 6	4.24992987615704e − 05	8.49985975231408e − 05	0.000127497896284711
n = 7	−6.07132839451006e − 06	−1.21426567890201e-05	−1.82139851835302e − 05
n = 10	−1.23904661112450e − 07	3.54013317464143e − 08	5.31019976196215e − 08
n = 14	−5.16054398635777e − 11	1.47444113895936e − 11	2.21166170843905e − 11
n = 18	−2.14933110635476e − 14	6.14094601815645e − 15	9.21141902723467e − 15
n = 21	6.26627144709842e − 17	−1.79036327059955e − 17	−2.68554490589932e − 17
n = 25	2.60985899504307e − 20	5.21971799008614e − 20	7.82957698512922e − 20
n = 26	−3.72836999291867e − 21	−7.45673998583735e − 21	−1.11851099787560e − 20
n = 27	0	0	0
n = 28	0	0	0